c) $A+2024 B=2035$

Q: c) $A+2024 B=2035$

A. True B. False Ta có: $A=\log _{2^{2030}} 4-\frac{1}{1015}+\ln e^{2035}=\log _{2^{2300}} 2^{2}-\frac{1}{1015}+2035$ $=\frac{2}{2030}-\frac{1}{1015}+2035=2035$.Ta có: $B=\log _{5} 3 \cdot \log _{2} 5-\frac{\ln 9}{\ln 4}=\log _{2} 5 \cdot \log _{5} 3-\log _{4} 9$ $=\log _{2} 3-\log _{2^{2}} 3^{2}=\log _{2} 3-\log _{2} 3=0$.

Question

c) $A+2024 B=2035$

Accepted Answer

A. True
B. False

Ta có: $A=\log _{2^{2030}} 4-\frac{1}{1015}+\ln e^{2035}=\log _{2^{2300}} 2^{2}-\frac{1}{1015}+2035$ $=\frac{2}{2030}-\frac{1}{1015}+2035=2035$.

Ta có: $B=\log _{5} 3 \cdot \log _{2} 5-\frac{\ln 9}{\ln 4}=\log _{2} 5 \cdot \log _{5} 3-\log _{4} 9$ $=\log _{2} 3-\log _{2^{2}} 3^{2}=\log _{2} 3-\log _{2} 3=0$.

Đề thi giữa kì 2 (Cấu trúc mới) - Đề số 16 - MĐ 10924