a) $\frac{x^{2}-2 x-8}{(x+1)\left(x^{2}-4 x+3\right)} \geq 0$.

Q: a) $\frac{x^{2}-2 x-8}{(x+1)\left(x^{2}-4 x+3\right)} \geq 0$.

Bảng xét dấu<figure class="image"><img alt="image.png" src="https://docdn.giainhanh.io/media/test/0da559dd2a95171a5697461e31a274d7.png" srcset="https://docdn.giainhanh.io/media/test/2f1e6abd248ff3cf967cecfd141e7dc1.png 245w, https://docdn.giainhanh.io/media/test/5bbb8d00d0fc71baeae09f45fb22bc8d.png 500w" sizes="100vw" width="500"></figure>Bpt $\Leftrightarrow-2 \leq x\lt -1 \vee 1\lt x\lt 3 \vee 4 \leq x$

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Bpt $\Leftrightarrow-2 \leq x\lt -1 \vee 1\lt x\lt 3 \vee 4 \leq x$

THPT Nguyễn Thị Minh Khai - Đề thi cuối kì 2 (CT) 18-19 - Q.3 - Tp. Hồ Chí Minh - MĐ 6355