c) $\frac{1}{6} \cdot \frac{2}{3}+\frac{1}{6} \cdot \frac{1}{3}-\frac{1}{6}$.

Q: c) $\frac{1}{6} \cdot \frac{2}{3}+\frac{1}{6} \cdot \frac{1}{3}-\frac{1}{6}$.

$\frac{1}{6} \cdot \frac{2}{3}+\frac{1}{6} \cdot \frac{1}{3}-\frac{1}{6}$$=\frac{1}{6} \cdot\left(\frac{2}{3}+\frac{1}{3}-1\right)$$=\frac{1}{6} \cdot 0$$=0$

Question

Accepted Answer

$\frac{1}{6} \cdot \frac{2}{3}+\frac{1}{6} \cdot \frac{1}{3}-\frac{1}{6}$

$=\frac{1}{6} \cdot\left(\frac{2}{3}+\frac{1}{3}-1\right)$

$=\frac{1}{6} \cdot 0$

$=0$

THCS Kiến Thiết - Đề thi cuối kì 2 (CT) 19-20 - Q. 3 - Tp. Hồ Chí Minh - MĐ 6275