c) $2 \frac{1}{2}+75 \%+\left(-\frac{1}{2}\right)^{2}-2020^{\circ}$

Q: c) $2 \frac{1}{2}+75 \%+\left(-\frac{1}{2}\right)^{2}-2020^{\circ}$

<p><span class="math-tex">$\begin{array}{l}2 \frac{1}{2}+75 \%+\left(-\frac{1}{2}\right)^{2}-2020^{\circ} \\ =\frac{5}{2}+\frac{3}{4}+\frac{1}{4}-1 \\ =\frac{5}{2}+1-1 \\ =\frac{5}{2}\end{array}$</span></p>

Question

Accepted Answer

$\begin{array}{l}2 \frac{1}{2}+75 \%+\left(-\frac{1}{2}\right)^{2}-2020^{\circ} \ =\frac{5}{2}+\frac{3}{4}+\frac{1}{4}-1 \ =\frac{5}{2}+1-1 \ =\frac{5}{2}\end{array}$

THCS Lê Lợi - Đề thi cuối kì 2 (CT) 19-20 - Q. 3 - TP. Hồ Chí Minh - MĐ 6488