d) $A-2024 B=2035$

Q: d) $A-2024 B=2035$

A. True B. False Ta có: $A=\log _{2^{2000}} 4-\frac{1}{1015}+\ln e^{2035}=\log _{2^{2000}} 2^{2}-\frac{1}{1015}+2035$\[=\frac{2}{2030}-\frac{1}{1015}+2035=2035 \text {. }\]Ta có: $B=\log _{5} 3 \cdot \log _{2} 5-\frac{\ln 9}{\ln 4}=\log _{2} 5 \cdot \log _{5} 3-\log _{4} 9$\[=\log _{2} 3-\log _{2^{2}} 3^{2}=\log _{2} 3-\log _{2} 3=0 \text {. }\]

Question

d) $A-2024 B=2035$

Accepted Answer

A. True
B. False

Ta có: $A=\log _{2^{2000}} 4-\frac{1}{1015}+\ln e^{2035}=\log _{2^{2000}} 2^{2}-\frac{1}{1015}+2035$

$$=\frac{2}{2030}-\frac{1}{1015}+2035=2035 \text {. }$$

Ta có: $B=\log _{5} 3 \cdot \log _{2} 5-\frac{\ln 9}{\ln 4}=\log _{2} 5 \cdot \log _{5} 3-\log _{4} 9$

$$=\log _{2} 3-\log _{2^{2}} 3^{2}=\log _{2} 3-\log _{2} 3=0 \text {. }$$

Đề thi giữa kì 2 (Cấu trúc mới) - Đề số 36 - MĐ 10939